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中二數 因式分解 help!!

發問:

1b) y2次方-25 2c) 36x次方-49y2次方 3b) x2次方+8x+16 4d) x2次方+26xy+169y2次方 5a) x2次方-12x+36 6b) a2次方-8ab+16b次方

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1.b. y2 – 25 = y2 - 52 = (y + 5)(y - 5) By using the identity, a2 – b2 = (a + b)(a - b) 2.c. 36x2 – 49y2 = (6x)2 – (7y)2 = (6x + 7y)(6x – 7y) 3.b. x2 + 8x + 16 = x2 + 2(4)x + 42 = (x + 4)2 Using (a2 + 2ab + b2) = (a + b)2 4.d. x2 + 26xy + 169y2 = x2 + 2x(13y) + (13y)2 = (x + 13y)2 5.a. x2 – 12x + 36 = x2 – 2x(6) + 62 = (x - 6)2 Using a2 – 2ab + b2 = (a - b)2 6.b. a2 – 8ab + 16b2 = a2 – 2a(4b) + (4b)2 = (a – 4b)2

其他解答:

1b) y2次方-25 =(y-5)(y+5) 2c) 36x次方-49y2次方 =(6x-7y)(6x+7y) 3b) x2次方+8x+16 =(x+4)^2 4d) x2次方+26xy+169y2次方 =(x+13)^2 5a) x2次方-12x+36 =(x-6)^2 6b) a2次方-8ab+16b次方 =(a-6b)^2
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