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標題:
Geometry
發問:
For triangle ABC, M is the mid-point of AC. P is a point on BC such that BP : PC = 2 : 1. Q is a point on AB and G is a point on BM such that QGP is a straight line and QG : GP = 3 : 4. Prove that Q is the mid- point of AB. 更新: Can 001 use geometric method? I don't understand vector.
最佳解答:
QG向量=(3/7)BP向量+(4/7)BQ向量 BM向量 =(1/2)BC向量+(1/2)BA向量 =(1/2)(3/2)BP向量+(1/2)(AB/BQ)BA向量 Since QG直線=QM直線 So (3/7)/(3/4)=(4/7)/[(1/2)(AB/BQ)] AB/BQ=2 So Q為 AB中點
其他解答:
Geometry
發問:
For triangle ABC, M is the mid-point of AC. P is a point on BC such that BP : PC = 2 : 1. Q is a point on AB and G is a point on BM such that QGP is a straight line and QG : GP = 3 : 4. Prove that Q is the mid- point of AB. 更新: Can 001 use geometric method? I don't understand vector.
最佳解答:
QG向量=(3/7)BP向量+(4/7)BQ向量 BM向量 =(1/2)BC向量+(1/2)BA向量 =(1/2)(3/2)BP向量+(1/2)(AB/BQ)BA向量 Since QG直線=QM直線 So (3/7)/(3/4)=(4/7)/[(1/2)(AB/BQ)] AB/BQ=2 So Q為 AB中點
其他解答:
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